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Find the x intercepts of y=2x^2+x-21

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Cam943idn
The x intercept is when y=0. Substitute: 

[tex]2x^2+x-21=0[/tex]

Solve for x by factoring.

[tex]2x^2-6x+7x-21=0[/tex]

[tex]=2x(x-3)+7(x-3)=0[/tex]

[tex]=(x-3)(2x+7)=0[/tex] 

[tex]x=3[/tex] AND [tex]x=-\frac{7}{2}[/tex] 

So therefore, we have our intercepts: 

(3,0) & (-7/2,0) 

Hope that helped!

~Cam943, Moderator


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