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If y varies jointly as x and z and y = 60 when x = 3 and z = 4, find y when x is 6 and z is 8. Can aanyone walk me through how to do this?
if y varies jointly with x & z then y = kxz k = constant > you need to find the constant first before you can solve this kind of problem 60 = k3*4 y = 60 when x is 3 & z is 4 12k = 60 k = 5 Thus y = 5*6*8 when x =6 & z =8 y = 240
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