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An alarm clock draws 0.5 A of current when connected to a 120 volt circuit. Calculate its resistance.

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We need to calculate the resistance of a clock which draws current I=0.5A and is connected to a circuit of V=120V. We can find the resistance of a circuit from Ohm's law: I=U/R where I is the current, U is the voltage and R is the resistance. So lets manipulate Ohm's law to find the resistance: R=U/I. Now we input our numbers: R=120V/0.5A and we get R=240 Ohm. So the resistance is R=240 Ohm.
Nuhulawal20idn

Given the amount of voltage and the amount of current drawn by the alarm clock, its resistance is 240 ohms.

What is Ohm’s law?

Ohm’s law states that "the potential difference between two points is directly proportional to the current flowing through the resistance.

It is expressed as;

V = I × R

Where V is the voltage or potential difference, potential difference, I is the current and R is the resistance.

Given the data in the question;

  • Voltage V = 120V
  • Current I = 0.5A
  • Resistance R = ?

We substitute our given values into the expression above.

V = I × R

120V = 0.5A × R

R = 120V / 0.5A

R = 240Ω

Therefore, given the amount of voltage and the amount of current drawn by the alarm clock, its resistance is 240 ohms.

Learn more about Ohm's law here: brainly.com/question/2364325

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