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find the slope of a line perpendicular to the line whose equation is 3y + 2x = 6

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Lilithidn
[tex]3y + 2x = 6\\ \\the \ slope \ intercept \ form \ is : \\ \\ y= mx +b \\ \\3y=-2x+6 \ \ /:3\\ \\y=-\frac{2}{3}x+\frac{6}{3}\\ \\y=-\frac{2}{3}x +2 \\ \\ m = -\frac{2}{3} \\ \\ Answer : \ slope \ is \ m = -\frac{2}{3}[/tex]
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