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Use the quadratic formula to solve x2 + 7x + 8 = 0. Estimate irrational solutions to the nearest tenth.

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Lilithidn
[tex]x^2 + 7x + 8 = 0\\ \\a=1, \ b=7 ,\ c=8 \\ \\ x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{-7-\sqrt{7^2-4 \cdot 1\cdot 8}}{2 \cdot 1}=\frac{-7-\sqrt{49-32}}{2}=\frac{-7-\sqrt{17}}{2}\\ \\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-7+\sqrt{7^2-4 \cdot 1\cdot 8}}{2 \cdot 1}=\frac{-7+\sqrt{49-32}}{2}=\frac{-7+\sqrt{17}}{2}[/tex]


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Answer:

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