Aphrodite1228idn
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1.Find the constant of variation for the relationship f(x)= 30x.  A.10  B.30  C.x  D.f(x)

2.Find the constant of variation for the relationship shown in the following table:
 x 1 2  3  4
y 4  8 12 16   

A.1  B.2  C.3  D.4

3.If f(x) varies directly with x, and f(x) = 8 when x = 6, write the direct linear variation equation.  A. f(x) = x  B.f(x) = 6x  C.f(x) = 8x  D.f(x) = x

4.If f(x) varies directly with x, and f(x) = 56 when x = 8, find the value of f(x) when x = 2  
A.4  B.7  C.8  D.14

5.Which does not show a direct variation between x and y? 
 A.y =   B.y = 2x  C.y = 0.5x  D.y = 

Sagot :

Kate200468idn
[tex](1)\\ f(x)=30x\ \ \ \Leftrightarrow\ \ \ \frac{f(x)}{x} =30\ \ \ \Rightarrow\ \ \ constant=30\ \ \ \Rightarrow\ \ \ Ans.\ B.\\\\(2)\\consatnt= \frac{y}{x} = \frac{4}{1} =4\ \ \ \Rightarrow\ \ \ Ans.\ D.\\\\(3)\\f(x)=m\cdot x\ \ \ and\ \ \ f(6)=8\\\\m\cdot6=8\ \ \ \Rightarrow\ \ \ m= \frac{8}{6} = \frac{4}{3} \ \ \ \Rightarrow\ \ \ y= \frac{4}{3}x\ \ \ \ Ans.\ (?)[/tex]

[tex](4)\\f(x)=m\cdot x\ \ and\ \ f(8)=56\\\\m\cdot8=56\ \ \Leftrightarrow\ \ m= \frac{56}{8} =7\ \ \Rightarrow\ \ \ f(x)=7x\ \ \ \Rightarrow\ \ \ f(2)=7\cdot2=14\\\\Ans.\ D.\\\\(5)\\direct:\ \ y=m\cdot x\ \ \ and\ \ \ m\in R\\e.g.:\ \ y=2x,\ \ y=0.5x,\ \ y= \frac{x}{7}= \frac{1}{7}x,\ ...\\\\NOT\ direct:\ \ \ e.g.:\ \ y= \sqrt{x} ,\ \ y= \frac{1}{x},\ \ y=x^2,\ ...[/tex]
Staceyloper78idn

the answer is D i have this test and its the right answer for 2 reasons

1,its the only thing that looks like english

2,its always the right answer in anime logic

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