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If x = - 2 and y = 3, what is the value of - x∧- y? the answer is 1/8. how? 

Sagot :

D3xt3Ridn
[tex]-x^{-y}[/tex]

You have to know that every number to negative power is the inverse, for example:

[tex]3^{-1}=\frac{1}{3^1}[/tex]

in this exercise we will make the same thing

when [tex]x=-2~~and~~y=3[/tex]

[tex]-(-2)^{-3}[/tex]

let's do the inverse

[tex]-\frac{1}{(-2)^3}[/tex]

now [tex](-2)^3=-8[/tex]

[tex]-\frac{1}{-8}[/tex]

doing the signal rule

[tex]\boxed{\boxed{\frac{1}{8}}}[/tex]
Ryan2idn
[tex]-x^{-y}\\ \\ -(-2)^{-3}=-\frac{1}{(-2)^3}=-\frac{1}{-8}=\frac{1}{8}[/tex]
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