Join IDNLearn.com and start exploring the answers to your most pressing questions. Our experts provide timely and accurate responses to help you navigate any topic or issue with confidence.

How do you have factor y=6x²+24x-192 and find the zeros?

Sagot :

[tex]y=6x^2+24x-192\\\\y=0\ \ \ \Leftrightarrow\ \ \ 6x^2+24x-192=0\ /:6\\\\x^2+4x-27=0\\\\x^2+2\cdot2\cdot x+2^2-2^2-27=0\\\\(x+2)^2-31=0\\\\(x+2)^2=31\ \ \ \Leftrightarrow\ \ \ (x+2= \sqrt{31} \ \ \ or\ \ \ x+2=- \sqrt{31})\\\\x=-2+ \sqrt{31}\ \ \ or\ \ \ x=-2- \sqrt{31}[/tex]