Vregian77idn
Answered

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(10y^3+20y^2+55y)/5y

Sagot :

( 10y^3 + 20y^2 +55y ) / 5y
= 2y^2 + 4y +11

And then depending on if the equation is set to zero in the problem, just factor or use the quadratic formula on the quadratic equation that is left.

Answer:

2y^2+4y+11

Step-by-step explanation:

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