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In how many ways can a committee of 6 be chosen from 5 teachers and 4 students if the committee must include 3 teachers and 3 students?

Sagot :

Crisforpidn
[5! / 3! * 2!] *[4! / 3! * 1!] = ( 20 / 2 ) * 4 = 40 ways;
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