Explore a diverse range of topics and get expert answers on IDNLearn.com. Find reliable solutions to your questions quickly and accurately with help from our dedicated community of experts.

How to find exact value of tan 75°

Sagot :

[tex]tan \alpha = \frac{sin \alpha }{cos \alpha } \\--------\\\\tan75^0= \frac{\big{sin75^0}}{\big{cos75^0}} \\\\sin75^0=sin(45^0+30^0)=sin45^0\cdot cos30^0+sin30^0\cdot cos45^0=\\\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ = \frac{ \sqrt{2} }{2} \cdot \frac{ \sqrt{3} }{2} + \frac{1}{2} \cdot\frac{ \sqrt{2} }{2} = \frac{ \sqrt{6}+ \sqrt{2} }{4} [/tex]