IDNLearn.com offers a comprehensive solution for all your question and answer needs. Whether it's a simple query or a complex problem, our experts have the answers you need.
Sagot :
Let's call:
[tex]first\#=x[/tex]
[tex]second\#=y[/tex]
then
when we have a SUM, we have PLUS and when we have a DIFFERENCE, we have MINUS... Let's go then...
[tex]\begin{Bmatrix}x+y&=&95\\x-y&=&61\end{matrix}[/tex]
now we can sum all the rows then we got it... (This is the other way to solved this question)
[tex]x+y+(x-y)=95+61[/tex]
[tex]x+y+x-y=156[/tex]
[tex]2x=156[/tex]
[tex]\boxed{x=78}[/tex]
now we can replace this value at first or at second row, you just need to pick up one...
I'll choose the second one
[tex]x-y=61[/tex]
[tex]78-y=61[/tex]
[tex]y=78-61[/tex]
[tex]\boxed{y=17}[/tex]
[tex]\boxed{\boxed{\begin{Bmatrix}x&=&78\\y&=&17\end{matrix}}}[/tex]
[tex]first\#=x[/tex]
[tex]second\#=y[/tex]
then
when we have a SUM, we have PLUS and when we have a DIFFERENCE, we have MINUS... Let's go then...
[tex]\begin{Bmatrix}x+y&=&95\\x-y&=&61\end{matrix}[/tex]
now we can sum all the rows then we got it... (This is the other way to solved this question)
[tex]x+y+(x-y)=95+61[/tex]
[tex]x+y+x-y=156[/tex]
[tex]2x=156[/tex]
[tex]\boxed{x=78}[/tex]
now we can replace this value at first or at second row, you just need to pick up one...
I'll choose the second one
[tex]x-y=61[/tex]
[tex]78-y=61[/tex]
[tex]y=78-61[/tex]
[tex]\boxed{y=17}[/tex]
[tex]\boxed{\boxed{\begin{Bmatrix}x&=&78\\y&=&17\end{matrix}}}[/tex]
[tex] \left \{ {x+y=95} \atop {x-y=61}} \right. \\
\\2x=156\\x= \frac{156}{2} \\
\\x=78\\
\\y=95-y\\y=95-78\\y=17[/tex]
First number 78, and the second is 17 .
First number 78, and the second is 17 .
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Thank you for choosing IDNLearn.com. We’re dedicated to providing clear answers, so visit us again for more solutions.