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Sagot :
Let's call:
[tex]first\#=x[/tex]
[tex]second\#=y[/tex]
then
when we have a SUM, we have PLUS and when we have a DIFFERENCE, we have MINUS... Let's go then...
[tex]\begin{Bmatrix}x+y&=&95\\x-y&=&61\end{matrix}[/tex]
now we can sum all the rows then we got it... (This is the other way to solved this question)
[tex]x+y+(x-y)=95+61[/tex]
[tex]x+y+x-y=156[/tex]
[tex]2x=156[/tex]
[tex]\boxed{x=78}[/tex]
now we can replace this value at first or at second row, you just need to pick up one...
I'll choose the second one
[tex]x-y=61[/tex]
[tex]78-y=61[/tex]
[tex]y=78-61[/tex]
[tex]\boxed{y=17}[/tex]
[tex]\boxed{\boxed{\begin{Bmatrix}x&=&78\\y&=&17\end{matrix}}}[/tex]
[tex]first\#=x[/tex]
[tex]second\#=y[/tex]
then
when we have a SUM, we have PLUS and when we have a DIFFERENCE, we have MINUS... Let's go then...
[tex]\begin{Bmatrix}x+y&=&95\\x-y&=&61\end{matrix}[/tex]
now we can sum all the rows then we got it... (This is the other way to solved this question)
[tex]x+y+(x-y)=95+61[/tex]
[tex]x+y+x-y=156[/tex]
[tex]2x=156[/tex]
[tex]\boxed{x=78}[/tex]
now we can replace this value at first or at second row, you just need to pick up one...
I'll choose the second one
[tex]x-y=61[/tex]
[tex]78-y=61[/tex]
[tex]y=78-61[/tex]
[tex]\boxed{y=17}[/tex]
[tex]\boxed{\boxed{\begin{Bmatrix}x&=&78\\y&=&17\end{matrix}}}[/tex]
[tex] \left \{ {x+y=95} \atop {x-y=61}} \right. \\
\\2x=156\\x= \frac{156}{2} \\
\\x=78\\
\\y=95-y\\y=95-78\\y=17[/tex]
First number 78, and the second is 17 .
First number 78, and the second is 17 .
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