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(Sint+cost)^2= ?

Can any one help me with this question

Sagot :

AL2006idn
The answer to your question is: Yes.

Now, would you like to actually see the solution ?

First, multiply the quantity out:

(sin + cos)² = sin²(t) + cos²(t) + 2sin(t)cos(t)

You need to know:
==> sin²(any angle) + cos²(the same angle) = 1
==> 2sin(any angle)cos(the same angle) = sin(double the angle)

So the equation becomes:

(sin + cos)² = 1 + sin(2t)



Kate200468idn
[tex](sin\ t+cos\ t)^2=sin^2t+cos^2t+2\cdot sin\ t\cdot cos\ t=1+sin\ 2t[/tex]
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