Get the information you need with the help of IDNLearn.com's extensive Q&A platform. Discover reliable and timely information on any topic from our network of knowledgeable professionals.
Sagot :
[tex]f(x)=2x^3-x^2-5x+6 \ \ \ \boxed{x=2}\\
\\
f(2)=2*2^3-2^2-5*2+6\\
\\
f(2)=16-4-10+6\\
\\
f(2)=8[/tex]
Answer:
A Function states an equation that has only one answer for y for every x. Also, a function assigns exactly one output to each input of a specified type.
i,e y= f(x) where x represents the input variable and y represents the output value.
Given the function: [tex]F(x) = 2x^3-x^2-5x+6[/tex]
Substitute the given input value of x =2 , we get;
[tex]F(2) = 2(2)^3-(2)^2-5(2)+6[/tex]
[tex]F(2) = 2(8)-4-10+6[/tex]
or
[tex]F(2) = 16-4-10+6[/tex]
Simplify:
[tex]F(2) = 8[/tex]
Therefore, the function [tex]F(x)=2x^3-x^2-5x+6[/tex] for x=2, we have F(2) =8.
We appreciate your contributions to this forum. Don't forget to check back for the latest answers. Keep asking, answering, and sharing useful information. Trust IDNLearn.com for all your queries. We appreciate your visit and hope to assist you again soon.