Answered

Get detailed and reliable answers to your questions with IDNLearn.com. Join our knowledgeable community and access a wealth of reliable answers to your most pressing questions.

Please solve and show work if you can!

Please Solve And Show Work If You Can class=

Sagot :

Konrad509idn
[tex]\frac{x+2}{2}\cdot\frac{4x+20}{x^2+6x+8}=\\ \frac{x+2}{2}\cdot\frac{2(2x+10)}{x^2+2x+4x+8}=\\ (x+2)\cdot\frac{2x+10}{x(x+2)+4(x+2)}=\\ (x+2)\cdot\frac{2x+10}{(x+4)(x+2)}=\\ \frac{2x+10}{x+4}[/tex]
Lilithidn
[tex]\frac{ x+2 }{2} \cdot \frac{ 4x+20 }{x^2+6x+8 } \\\\x^2+6x+8\neq 0\\ \\x^2+4x +2x+8 \neq 0 \\ \\ x(x+4)+2(x+4)\neq 0\\ \\(x+4)(x+2)\neq 0[/tex]

[tex]x+4 \neq 0 \ \ \wedge \ \ x+2\neq 0\\ \\ x\neq -4 \ \ \wedge \ \ x\neq -2 \\ \\ D=R\setminus \left \{ -4,-2 \right \}[/tex]

[tex]\frac{ x+2 }{2} \cdot \frac{ 4x+20 }{x^2+6x+8 } =\frac{\not( x+2 )^1}{\not2^1} \cdot \frac{ \not4^2(x+5) }{\not(x+2)^1(x+4) } =\frac{2(x+5)}{x+4}[/tex]


Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and see you next time for more reliable information.