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The larger leg of a right triangle is 3 cm longer than it's smaller leg.The hypotenuse is 6 cm longer than smaller leg. How many centimeters long  is the smaller leg

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Ryan2idn
From the text of the task we have:

smaller leg:   x
longer leg:  x+3
hypotenuse: x + 6

Using the Pythagorean Theorema:

[tex](x+6)^2=x^2+(x+3)^2\\ \\ x^2+12x+36=x^2+x^2+6x+9\\ \\ x^2-6x-27=0\\ \\ \Delta=(-6)^2-4.1.(-27)=36+108=144\\ \\ x=\frac{6 \pm \sqrt{144}}{2}=\frac{6 \pm 12}{2}\\ \\ x_1=-3\\ \\ x_2=9[/tex]

Obviously -3 is not possible, so, smaller leg is 9 cm
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