Discover new knowledge and insights with IDNLearn.com's extensive Q&A platform. Get comprehensive and trustworthy answers to all your questions from our knowledgeable community members.

how i can solve this square of binomial (3z+2k)2?

Sagot :

You can solve this by the 1st identity which is (a+b)=a^2+b^2+2ab
(3z)^2+(2k)^2+2*3z*2k
=9z^2+4k^2+12kz
[tex](3z+2k)^2=(3z)^2+2\cdot 3z\cdot 2k +(2k)^2 = 9z^2 + 12kz +4k^2[/tex]


We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Find the answers you need at IDNLearn.com. Thanks for stopping by, and come back soon for more valuable insights.