Stoneecoldamberidn
Answered

Explore IDNLearn.com's extensive Q&A database and find the answers you need. Get accurate and comprehensive answers to your questions from our community of knowledgeable professionals.


(x[tex](x^{2}-6x-16)divided(x+2)
[/tex]

Sagot :

Lilithidn
[tex]\frac{x^{2}-6x-16}{x+2}=\frac{x^{2}-6x-2x+2x-16}{x+2}=\frac{x^{2}-8x +2x-16}{x+2}=\\ \\ = \frac {( x -8 ) +2(x-8)}{x+2}=\frac {( x -8 )(x +2)}{x+2}=x-8[/tex]


Crisforpidn
In algebra, the polynomial remainder theorem or little Bézout's theorem is an application of Euclidean division of polynomials. It states that the remainder of the division of a polynomial  by a linear polynomial  is equal to  In particular,  is a divisor of  if and only if 

a = -2;
f(-2) = (-2)^2 -6*(-2) -16 = 4 + 12 - 16 = 0 => x-(-2) is a divisor of x^2-6x-16.
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. Thank you for visiting IDNLearn.com. We’re here to provide clear and concise answers, so visit us again soon.