Answered

IDNLearn.com: Your reliable source for finding expert answers. Get comprehensive answers to all your questions from our network of experienced experts.

How do I solve n^2-5n-14=0 by factoring

Sagot :

(N-7)(n+2)=0 as you'd get n^2-7n+2n-14 then just simplify. Then it would be n=-2 or 7
Konrad509idn
[tex]n^2-5n-14=0 \\ n^2-7n+2n-14=0\\ n(n-7)+2(n-7)=0\\ (n+2)(n-7)=0\\ n=-2 \vee n=7[/tex]
Your engagement is important to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Thank you for visiting IDNLearn.com. We’re here to provide dependable answers, so visit us again soon.