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5 times the smaller number of two consecutive numbers is added to 3 times the bigger, the result is 579. find the smaller number

Sagot :

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Give the smaller number a name. Call it ' Q '.
The numbers are consecutive, so the larger number is (Q + 1) .

Five times the smaller number is 5Q .
Three times the bigger number is 3(Q+1) = 3Q+3 .

The problem says that when you add all this up ... 5Q + (3Q+3) ... you get 579.

5Q + 3Q + 3 = 579

Clean up the left side:

8Q + 3 = 579

Subtract 3 from each side:

8Q = 576

Divide each side by 8 :

Q = 72

The smaller number is 72, and the larger number is 73.
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