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Sagot :
The coordinates of the midpoint are just the average of the endpoint coordinates ...
x-mid is the average of the end-x's, and y-mid is the average of the end-y's.
P. x = 0, y = 8
Q. x = 4, y = 2
'x' of the midpoint is the average of 0 and 4 = (1/2)(0 + 4) = 2
'y' of the midpoint is the average of 8 and 2 = (1/2)(8 + 2) = 5
The midpoint is (2, 5) .
That's choice-'c'.
x-mid is the average of the end-x's, and y-mid is the average of the end-y's.
P. x = 0, y = 8
Q. x = 4, y = 2
'x' of the midpoint is the average of 0 and 4 = (1/2)(0 + 4) = 2
'y' of the midpoint is the average of 8 and 2 = (1/2)(8 + 2) = 5
The midpoint is (2, 5) .
That's choice-'c'.
There is midpoint formula for this problem:[ (x1+x2)/2, (y1+y2)/2 ], so all you need to do is plug in points given P(x1=0, y1=8) and Q(x2=4, y2=2), which is [ (0+4)/2, (8+2)/2 ]= [ 2, 5], so the answer is c)
Hope this helps!
Hope this helps!
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