how to solve 2^(log(2)3+ log(2)5

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18-06-2014
Mathematics

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how to solve 2^(log(2)3+ log(2)5

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Konrad509idn Konrad509idn · Answer 1 · 2014-06-18T17:32:12-04:00

Konrad509idn Konrad509idn

18-06-2014

[tex]2^{\log_23+ \log_25 }=\\ 2^{\log_215}=\\ 15[/tex]

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Анонимidn Анонимidn · Answer 2 · 2014-06-20T06:23:58-04:00

Анонимidn Анонимidn

20-06-2014

[tex]2^{log_23+log_25}=2^{log_2(3\cdot5)}=2^{log_215}=15\\\\---------------------------\\\\for\ a,b,c\in\mathbb{R^+}\\\\log_ab+log_ac=log_a(b\cdot c)\\\\a^{log_ab}=b[/tex]

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