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how to solve 2^(log(2)3+ log(2)5

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Konrad509idn
[tex]2^{\log_23+ \log_25 }=\\ 2^{\log_215}=\\ 15[/tex]
[tex]2^{log_23+log_25}=2^{log_2(3\cdot5)}=2^{log_215}=15\\\\---------------------------\\\\for\ a,b,c\in\mathbb{R^+}\\\\log_ab+log_ac=log_a(b\cdot c)\\\\a^{log_ab}=b[/tex]
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