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What is the magnitude of the electric field at a point 0.0075 m from a 0.0035 C charge?
In an electric field force,F= q₁q₂/4πε₀ r² (coulomb's law) as we know,F=qE E=F/q E=q/4πε₀ r² here,r= 0.0075 m q= 0.0035 C 1/4πε₀ = 9×10⁹ E= 9×10⁹× 0.0035/(0.0075)² =5.6 ×10¹¹ N/C
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