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Sagot :
We'll represent the distance as d and the time as t.
d= 3(t+7) because Gilda is 7 minutes late when travelling 3 mph
d= 4(t-5) because Gilda is 5 minutes early at 4 mph
d= 3t + 21
d= 4t -20
3t +21 =4t -20
41=t
d= 3(41) +21= 144
The distance is 144 miles.
d= 3(t+7) because Gilda is 7 minutes late when travelling 3 mph
d= 4(t-5) because Gilda is 5 minutes early at 4 mph
d= 3t + 21
d= 4t -20
3t +21 =4t -20
41=t
d= 3(41) +21= 144
The distance is 144 miles.
[tex]d=3(t + 7)\ \ \ if\ Gilda\ walks\ of\ 3mph\\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ she\ is\ 7\ minutes\ after\ departure\ of\ the\ train\\\\ d= 4(t - 5)\ \ \ if\ Gilda\ walks\ of\ 4mph\ \\.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ she\ is\ 5\ minutes\ before\ the\ train\ \\\\3(t+7)=4(t-5)\\\\3t + 21 = 4t - 20 \\\\t = 41\ \ \ \Rightarrow\ \ \ d=3(t+7)=3\cdot(41+7)=3\cdot48=144\\\\Ans.\ The\ distance\ to\ the\ station\ is\ 144\ miles.[/tex]
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