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Sagot :
Reaction:
HCl + NaOH ---> NaCl + H2O
1 mole of HCl = 36,5 g
1 mole of NaOH = 40g
so, according to the reaction:
1 mol HCl = 1 mol NaOH
so, we need > 36,5 g HCl (hydrochloric acid)
answer: 36,5 g HCl (hydrochloric acid)
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next question.
1 mole of NaCl = 58,5 g
1 mole of H2O = 18g
so, according to the reaction:
1 mole of HCl (36,5 g) ----------------- - 1 mole of NaCl (58,5 g)
(the same for NaOH)
i
1 mole of HCl (36,5 g) ------------------ 1 mole of H2O (18 g)
(the same for NaOH)
so, this reaction is stechiometric
answer: 58,5 g NaCl i 18g H2O
HCl + NaOH ---> NaCl + H2O
1 mole of HCl = 36,5 g
1 mole of NaOH = 40g
so, according to the reaction:
1 mol HCl = 1 mol NaOH
so, we need > 36,5 g HCl (hydrochloric acid)
answer: 36,5 g HCl (hydrochloric acid)
~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~ ~
next question.
1 mole of NaCl = 58,5 g
1 mole of H2O = 18g
so, according to the reaction:
1 mole of HCl (36,5 g) ----------------- - 1 mole of NaCl (58,5 g)
(the same for NaOH)
i
1 mole of HCl (36,5 g) ------------------ 1 mole of H2O (18 g)
(the same for NaOH)
so, this reaction is stechiometric
answer: 58,5 g NaCl i 18g H2O
HCl + NaOH ---> NaCl + H2O
1 mol HCl = 1 mol NaOH
mole HCl = 36.5 g // mole HaOH = 40 g
36.5 HCl is the answer.
mole NaCl = 58,5 g // mole H2O = 18g
HCl (36,5 g) ⇒ NaCl (58,5 g)
HCl (36,5 g) ⇒ H2O (18 g)
So, 58,5 g NaCl and 18 g H2O are the answer.
1 mol HCl = 1 mol NaOH
mole HCl = 36.5 g // mole HaOH = 40 g
36.5 HCl is the answer.
mole NaCl = 58,5 g // mole H2O = 18g
HCl (36,5 g) ⇒ NaCl (58,5 g)
HCl (36,5 g) ⇒ H2O (18 g)
So, 58,5 g NaCl and 18 g H2O are the answer.
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