Answered

Discover a wealth of information and get your questions answered on IDNLearn.com. Get prompt and accurate answers to your questions from our community of experts who are always ready to help.

Can someone help with number 4 please

Can Someone Help With Number 4 Please class=

Sagot :

AL2006idn
The way I look at these things is like this:

-- The runner covered 12 meters in 4 seconds.
Average speed = 3 meters per second.

-- Speed at the beginning = zero.
In order to make the average 3, Speed at the end = 6 meters per second.

-- Speed increased from zero to 6 meters per second in 4 seconds.
It must have increased 1.5 meters per second each second.

That's choice-#2.
Sairahidn
Here we have - 
Acceleration (a) = ?
Initial velocity (u) = 0 m/s (runner starts from rest)
Distance (s) = 12 m
Time (t) = 4 seconds

So, using the second equation of motion, we have-

[tex]s = ut + \frac{1}{2}at^{2} [/tex]

[tex]12 = 0*4 + \frac{1}{2}*a*4 ^{2} [/tex]

[tex]12 = 0+8a[/tex]

[tex] \frac{12}{8} = a[/tex]

[tex]1.5m/ s^{2} [/tex]

So, option (2) is correct.
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is your source for precise answers. Thank you for visiting, and we look forward to helping you again soon.