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The larger leg of a right triangle is 3cm longer than its smaller leg. The hypotenuse is 6cm longer than the smaller leg. how many centimeters long is the smaller leg  

please explain how you got it 

Sagot :

Konrad509idn
[tex]b=a+3\\ c=a+6\\ a^2+b^2=c^2\\\\ a^2+(a+3)^2=(a+6)^2\\ a^2+a^2+6a+9=a^2+12a+36\\ a^2-6a-27=0\\ a^2-9a+3a-27=0\\ a(a-9)+3(a-9)=0\\ (a+3)(a-9)=0\\ a=-3 \vee a=9\\ [/tex]

The length can't be negative, so the answer is 9 cm.
View image Konrad509
Tadvisohil886idn
Let the smaller leg be x.

Thus, larger leg = 3 +x
Thus, hypotenuse = 6 + x

Applying pythagoras theorum ;

[tex](6+x)^2 = x^2 + (3+x)^2 \\ \\ or, 6^2 + 12x + x^2 = 3^2 + 6x + x^2 \\ \\ i.e., 36 + 12x = 9 + 6x \\ \\ =>6x = 45 \\ \\ => x = 9[/tex]

Thus, the length of smaller peg is 9 cm.
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