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White phosphorus, P4, is prepared by fusing
calcium phosphate, Ca3(PO4)2, with carbon, C,
and sand, SiO2, in an electric furnace.




2Ca3(PO4)2(s) + 6SiO2(s)
+ 10C(s) --> P4(g)
+ 6CaSiO3(l) + 10CO(g)




How many grams of calcium phosphate are required to give
30.0 g of phosphorus?

Think it's 150. g Ca3(PO4)2 (am I right or wrong? Please explain, thanks)