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a⁴+b⁴=a²b² ,prove that a⁶+b⁶=0

Sagot :

[tex]a^4+b^4=a^2b^2\\ a^4-a^2b^2+b^4=0\\ a^4-2a^2b^2+b^4+a^2b^2=0\\ (a^2+b^2)^2=-a^2b^2[/tex]

The only possible option is that [tex]a^2+b^2=0 \wedge a^2b^2=0\\[/tex] and this condition is met only when [tex]a=0 \wedge b=0[/tex].

[tex]0^6+0^6=0\\ 0=0[/tex]