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An antacid tablet containing 0.50 g of NaHCO3 is dissolved in 250 mL of water. What is the molar concentration of NaHCO3 in the solution?

Sagot :

Pyromorphiteidn
1 mole of NaHCO3 = 84g

1 mole of NaHCO3--------------84g
x moles of NaHCO3----------0,50g
x = 0,00595 moles of NaHCO3

0,00595 moles of NaHCO3----------in--------250ml
x moles of NaHCO3-------------------in-----------1000ml
x = 0,0238 moles of NaHCO3

answer: the molar concentration of NaHCO3 is 0,0238mol/l

Dexteright02idn

Hello!

An antacid tablet containing 0.50 g of NaHCO3 is dissolved in 250 mL of water. What is the molar concentration of NaHCO3 in the solution ?

  • We have the following data:

M (Molar Concentration or Molarity) = ? (in mol/L)

m (mass) = 0.50 g

V (volume) = 250 mL → 0.25 L

MM (Molar Mass of NaHCO3)

Na = 1*(23u) = 23 u

H = 1*(1u) = 1 u

C = 1*(12u) = 12 u

O = 3*(16u) = 48 u

-------------------------------

MM (Molar Mass of NaHCO3) = 23 + 1 + 12 + 48 = 84 g/mol

  • We apply the data found to the formula of molar Concentration or Molarity, let's see:

[tex]M = \dfrac{m}{MM*V}[/tex]

[tex]M = \dfrac{0.50}{84*0.25}[/tex]

[tex]M = \dfrac{0.50}{21}[/tex]

[tex]M = 0.023809... \to \boxed{\boxed{M \approx 0.024\:mol/L}}\:\:\:\:\:\:\bf\purple{\checkmark}[/tex]

Answer:  

The Molar Concentration is approximately 0.024 mol/L

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