Get the information you need from a community of experts on IDNLearn.com. Our experts are ready to provide prompt and detailed answers to any questions you may have.

How many grams of carbon dioxide (CO2) are found
in a 11.9 L container under 1.5 atm and 20.0oC.


Sagot :

pV=nRT

p = 1,5atm = 1,5*101325 = 151987,5 Pa
V = 11,9l = 0,0119m3
n = ?
R = 8,314 J/mol*K
T = 20°C = 20+273 = 293K

pV=nRT
151987,5*0,0119 = n*8,314*293
1808,6513=n*2436,002  ||:2436,002
0,7425 = n >>> moles of CO2

1 mole of CO2 = 44g

1 mole of CO2--------------44g
0,7425 moles of CO2----------x
x = 32,67g of CO2