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Sagot :
[tex]f(x+1)=(x+1)^3-3(x+1)^2+3(x+1)-1\\ f(x+1)=x^3+3x^2+3x+1-3(x^2+2x+1)+3x+3-1\\ f(x+1)=x^3+3x^2+6x+3-3x^2-6x-3\\ f(x+1)=x^3 \Rightarrow C[/tex]
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