IDNLearn.com offers a unique blend of expert answers and community-driven insights. Ask your questions and receive reliable and comprehensive answers from our dedicated community of professionals.

A wire 2 m long, 0.1 mm in diameter and has resistance of 20 ohm. Calculate the resistivityof its material.

Sagot :

R=[tex] \frac{pL}{A} [/tex]

R-resistance
p-resistivity [Ohm*m]
A-cross sectional area
L-length
R=20 Ohm
l=2m
A=[tex] \pi r^{2} [/tex]=[tex] \pi (0,01)^{2} =0,000314 cm^{2} [/tex]=0,314*[tex] 10^{-7} [/tex]m²
p=[tex] \frac{R*A}{L} [/tex]
p=[tex] \frac{20*0,314*10^{-7}}{2} [/tex]=0,000000314 Ohm*m
Your participation is crucial to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. Your questions deserve accurate answers. Thank you for visiting IDNLearn.com, and see you again for more solutions.