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A wire 2 m long, 0.1 mm in diameter and has resistance of 20 ohm. Calculate the resistivityof its material.

Sagot :

Luanaidn
R=[tex] \frac{pL}{A} [/tex]

R-resistance
p-resistivity [Ohm*m]
A-cross sectional area
L-length
R=20 Ohm
l=2m
A=[tex] \pi r^{2} [/tex]=[tex] \pi (0,01)^{2} =0,000314 cm^{2} [/tex]=0,314*[tex] 10^{-7} [/tex]m²
p=[tex] \frac{R*A}{L} [/tex]
p=[tex] \frac{20*0,314*10^{-7}}{2} [/tex]=0,000000314 Ohm*m
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