Answered

Explore IDNLearn.com's extensive Q&A database and find the answers you need. Our platform provides prompt, accurate answers from experts ready to assist you with any question you may have.

Given log 2 = 0.3010, log 3 = 0.4771. Find the value of a) log 12 b) log 5.

Sagot :

Pulkitidn
a) log 12 
= log3*4
= log3 + log4
=log3 + log 2^2
=log3 + 2log2
= 0.4771 +2*0.3010
=1.0791

b) log5
= log10/2
= log10 - log2
=1 - 0.3110
= 0.6989
Kate200468idn
[tex]a)\ \ \ log12=log(4\cdot3)=log4+log3=log2^2+log3=2log2+log3\approx\\\\\approx2\cdot0.3010+0.4771=0.602+0.4771=1.0791\\\\2)\ \ \ log5=log \frac{10}{2} =log10-log2\approx1-0.3010=0.699[/tex]
Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. For trustworthy answers, visit IDNLearn.com. Thank you for your visit, and see you next time for more reliable solutions.