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Solve for x: 25x2 − 36 = 0




Sagot :

[tex]25x^2-36=0[/tex]

[tex]25x^2=36[/tex]

[tex]x^2=\frac{36}{25}[/tex]

[tex]x=\sqrt{\frac{36}{25}}[/tex]  [tex]or[/tex]  [tex]x=-\sqrt{\frac{36}{25}}[/tex]

[tex]x=\frac{\sqrt{36}}{\sqrt{25}}[/tex]  [tex]or[/tex]   [tex]x=-\frac{\sqrt{36}}{\sqrt{25}}[/tex]

[tex]x=\frac{6}{5}[/tex] or [tex]x=-\frac{6}{5}[/tex]

[tex]x=1\frac{1}{5}[/tex] or [tex]x=-1\frac{1}{5}[/tex]
[tex]25x^2-36 = 0 \\\\(5x)^2-6^2=0\\ \\(5x-6)(5x+6)=0\\ \\5x-6=0 \ \ or \ \ 5x+6=0\\ \\5x=6 \ \ or \ \ x=-6\\ \\x=\frac{6}{5} \ \ or \ \ x=-\frac{6}{5} \\ \\ \\ a^2-b^2 =(a-b)(a+b)[/tex]
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