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let f(x)=2x+2. solve f^-1(x) when x=4.

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Konrad509idn
[tex]f(x)=2x+2\\ y=2x+2\\ 2x=y-2\\ x=\frac{1}{2}y-1\\ f^{-1}(x)=\frac{1}{2}x-1\\ f^{-1}(4)=\frac{1}{2}\cdot4-1\\ f^{-1}(4)=2-1\\ f^{-1}(4)=1 [/tex]
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Your answer is 1. Your welcome :)


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