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Factor completely 2x3 + x2 - 18x – 9.



Sagot :

[tex]2x^3+x^2-18x-9=x^2(2x+1)-9(2x+1)\\\\=(2x+1)(x^2-9)=(2x+1)(x^2-3^2)\\\\=(2x+1)(x-3)(x+3)[/tex]
[tex]2x^3 + x^2 - 18x - 9=x^2(2x+1)-9(2x+1)=\\ \\=(2x+1)(x^2-9)=(2x+1)(x-3)(x+3)[/tex]