Answered

Get the answers you've been searching for with IDNLearn.com. Our platform is designed to provide reliable and thorough answers to all your questions, no matter the topic.

sinxtanx=secx-cosx Please help me solve it

Sagot :

Ryan2idn
[tex]sinx.tanx=secx-cosx\\ \\ sinx.\frac{sinx}{cosx}=\frac{1}{cosx}-cosx\\ \\ \frac{sin^2x}{cosx}=\frac{1-cos^2x}{cosx}\\ \\ \frac{sin^2x}{cosx}=\frac{sin^2x}{cosx}[/tex]
Your engagement is important to us. Keep sharing your knowledge and experiences. Let's create a learning environment that is both enjoyable and beneficial. IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.