sinxtanx=secx-cosx Please help me solve it

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14-07-2014
Mathematics

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sinxtanx=secx-cosx Please help me solve it

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Ryan2idn Ryan2idn · Answer 1 · 2014-07-14T19:42:57-04:00

Ryan2idn Ryan2idn

14-07-2014

[tex]sinx.tanx=secx-cosx\\ \\ sinx.\frac{sinx}{cosx}=\frac{1}{cosx}-cosx\\ \\ \frac{sin^2x}{cosx}=\frac{1-cos^2x}{cosx}\\ \\ \frac{sin^2x}{cosx}=\frac{sin^2x}{cosx}[/tex]

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