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Solve for F: C=5/9(F-32)
please explain process thanks

Sagot :

[tex]C=\frac{5}{9}(F-32)\ \ \ \ /\cdot\frac{9}{5}\\\\F-32=\frac{9}{5}C\ \ \ \ /+32\\\\F=\frac{9}{5}C+32\\\\F=\frac{9C}{5}+\frac{160}{5}\\\\F=\frac{9C+160}{5}[/tex]
AL2006idn
C = 5/9 (F - 32)

Multiply each side by 9/5 :

9/5 C = F - 32

Add 32 to each side:

F = 9/5C + 32
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