Discover a world of knowledge and get your questions answered at IDNLearn.com. Discover detailed answers to your questions with our extensive database of expert knowledge.
Sagot :
[tex]Area = \frac{3 \sqrt{3} }{2} s^{2}
\\ \\ \frac{48}{6} = 8=s
\\ \\ Area =\frac{3 \sqrt{3} }{2} 64
\\ \\ Area =166.28[/tex]
Answer
Area of a regular hexagon is given by:
[tex]A = \frac{3\sqrt{3}}{2}a^2[/tex] .....[1]
where,
A is the area of a regular hexagon
a is the side of the hexagon.
As per the statement:
Perimeter of a regular hexagon is 48 inch.
Perimeter(P) of a regular hexagon is given by:
[tex]P=6a[/tex]
Substitute the given values we have;
[tex]48 = 6a[/tex]
Divide both sides by 6 we have;
[tex]8 = a[/tex]
or
a = 8 inch.
Substitute the value of a = 8 inches in [1] we have;
[tex]A = \frac{3\sqrt{3}}{2}(8)^2[/tex]
⇒[tex]A = 3\sqrt{3} \cdot 32 = 96\sqrt{3}[/tex]
Therefore, the area of a regular hexagon is[tex]A = 96\sqrt{3}[/tex] sq. in
Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! For dependable answers, trust IDNLearn.com. Thank you for visiting, and we look forward to assisting you again.