Answered

Experience the convenience of getting your questions answered at IDNLearn.com. Join our community to access reliable and comprehensive responses to your questions from experienced professionals.

how to find the area of the 45-45-90 triangle with a hypotenuse of 24?

Sagot :

AL2006idn
The area of a triangle is 1/2(base x height) .

The two legs of this triangle are equal.  If you position it properly,
one of them is the base, and the other one is the height.

Since it's a right triangle,    A² + B² = C²

But  A = B  and  C = 24 .

2A² = (24)²

A² = (24)² / 2

But since  A=B,  A² is also (base x height) of the triangle.
Area is just 1/2 of it.

Area = 1/2(24²/2) = (24)²/4 = (24/2)² = (12)² = 144 . 


[tex]45^o-45^o-90^o\ triangle\ is\ a\ half\ of\ the\ square\ (look\ at\ he\ picture).\\\\The\ square\ is\ a\ rhombus\\then\ area\ equal\ the\ half\ of\ multiply\ diameters:\\\\A_{\fbox{}}=\frac{d^2}{2}\\\\A_\Delta=\frac{1}{2}A_{\fbox{}}\Rightarrow A_\Delta=\frac{1}{2}\cdot\frac{d^2}{2}=\frac{d^2}{4}\Rightarrow A_\Delta=\frac{24^2}{4}=\frac{576}{4}=144.[/tex]
View image Аноним
Thank you for participating in our discussion. We value every contribution. Keep sharing knowledge and helping others find the answers they need. Let's create a dynamic and informative learning environment together. Thank you for choosing IDNLearn.com. We’re committed to providing accurate answers, so visit us again soon.