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A regular hexagon has sides of 5 feet. What is the area of the hexagon


Sagot :

[tex]a=5ft\\\\Area\ of\ the\ haxagon:A=6\cdot\frac{a^2\sqrt3}{4}=\frac{3a^2\sqrt3}{2}\\\\A=\frac{3\cdot5^2\sqrt3}{2}=\frac{3\cdot25\sqrt3}{2}=\frac{75\sqrt3}{2}\ (ft^2)[/tex]
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