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find the equation of the line that passes through (-2,3) and (4,-1).
the formula I believe is y-y1 = y2-y1/x2-x1 (x-x1)
I'm not quite sure as to how to set that up. do I solve as I go?

Sagot :

Luanaidn
[tex]Genera\ equation\ for\ line\\\\y=ax+b\\\\To\ find\ a\ and\ b\ substitude\ points\ (-2,3),\ (4,-1)\ into\ equation\\\\ \left \{ {{3=-2a+b}\ \ \ \ \atop {-1=4a+b\ |*-1}} \right.\\\\ \left \{ {{3=-2a+b}\ \ \ \ \atop {1=-4a-b\}} \right.\\+----\\\\Addition\ method\\\\4=-6a\ \ |:-6\\\\a=-\frac{4}{6}=-\frac{2}{3}\\\\b=3+2a=3+2* (-\frac{2}{3})=3-\frac{4}{3}=1\frac{2}{3}\\\\y=-\frac{2}{3}x+1\frac{2}{3}[/tex]
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