Get detailed and accurate answers to your questions on IDNLearn.com. Our Q&A platform is designed to provide quick and accurate answers to any questions you may have.
Sagot :
The square before the transformation would have side lengths of 5 since 5*4=20
so increasing the length and decreasing the width would make the square a rectangle with dimensions 7×4.
a=LW
a=(7)(4)
=28ft²
so increasing the length and decreasing the width would make the square a rectangle with dimensions 7×4.
a=LW
a=(7)(4)
=28ft²
All 4 sides of a square are the same length.
If the perimeter of the square is 20-ft, then each side is 20-ft/4 = 5 ft.
If you increase the length of the square by 2-ft, then its new length is 5+2 = 7-ft.
If you decrease the width of the square by 1-ft, then its new width is 5-1 = 4-ft.
The area of the new figure is (length) x (width) = (7-ft x 4-ft) = 28 square feet.
If the perimeter of the square is 20-ft, then each side is 20-ft/4 = 5 ft.
If you increase the length of the square by 2-ft, then its new length is 5+2 = 7-ft.
If you decrease the width of the square by 1-ft, then its new width is 5-1 = 4-ft.
The area of the new figure is (length) x (width) = (7-ft x 4-ft) = 28 square feet.
We appreciate your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. Thank you for choosing IDNLearn.com. We’re here to provide reliable answers, so please visit us again for more solutions.