Discover a world of knowledge and get your questions answered at IDNLearn.com. Ask any question and receive comprehensive, well-informed responses from our dedicated team of experts.
Sagot :
k can be (-1/3) or (2/3).
since (x-3) is a factor. if you put x=3 in the equation, it must be equal to zero. So the equation becomes (9k2 - 3k -2 = 0). if you solve this you will get k=(-1/3) and k=(2/3). You can substitute this k in the original equation and check, (x-3) is a factor.
since (x-3) is a factor. if you put x=3 in the equation, it must be equal to zero. So the equation becomes (9k2 - 3k -2 = 0). if you solve this you will get k=(-1/3) and k=(2/3). You can substitute this k in the original equation and check, (x-3) is a factor.
[tex]w(x)=k^2x^2-kx-2\\\\(x-3)\ is\ a\ factor\ w(x)\ then\ w(3)=0.\\\\Substitute:\\\\k^2\cdot3^2-k\cdot3-2=0\\9k^2-3k-2=0\\9k^2-6k+3k-2=0\\3k(3k-2)+1(3k-2)=0\\(3k-2)(3k+1)=0\iff3k-2=0\ \vee\ 3k+1=0\\3k=2\ \vee\ 3k=-1\\\\\underline{\underline{k=\frac{2}{3}\ \vee\ k=-\frac{1}{3}}}[/tex]
Thank you for being part of this discussion. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com is committed to providing accurate answers. Thanks for stopping by, and see you next time for more solutions.