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solve for t

d=(1/2) at^2


Sagot :

[tex]\frac{1}{2}at^2=d\ \ \ \ |multiply\ both\ sides\ by\ 2\\\\at^2=2d\ \ \ \ |divide\ both\ sides\ by\ a\\\\t^2=\frac{2d}{a}\ \ \ \ |square\ root\ both\ sides\\\\t=\sqrt\frac{2d}{a}[/tex]
[tex]d=\frac{1}{2}at^2\\ 2d=at^2\\ t^2=\frac{2d}{a}\\ t=\sqrt{\frac{2d}{a}}[/tex]