IDNLearn.com is the perfect place to get answers, share knowledge, and learn new things. Our community provides timely and precise responses to help you understand and solve any issue you face.

The area of the garden is 160 meter squared.Suppose the length of the garden is 3m more than twice its width.What is the length of the garden?

Sagot :

[tex]w-width\\\\2w+3-length\\\\160m^2-area\ of\ the\ garden\\\\w\time(2w+3)-area\ of\ the\ garden\\\\w(2w+3)=160\\\\2w^2+3w-160=0[/tex]

[tex]a=2;\ b=3;\ c=-160\\\\\Delta=b^2-4ac\to\Delta=3^2-4\cdot2\cdot(-160)=9+1240=1249\\\\w_1=\frac{-b-\sqrt\Delta}{2a};\ w_2=\frac{-b+\sqrt\Delta}{2a}\\\\\sqrt\Delta=\sqrt{1249}\approx35.34\\\\w_1=\frac{-3-35.34}{2\cdot2} < 0;\ w_2=\frac{-3+35.34}{2\cdot2}=\frac{32.34}{4}=8.085\ (m)\\\\length\approx2\cdot8.085+3=19.17\ (m)[/tex]