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Determine the equation of the line, in point-slope form, that will get your spacecraft from Point A (0,3) to Point B (-3,0)

Sagot :

Iloveonedirectionidn
[tex]m= \frac{y2-y1}{x2-x1} [/tex]

[tex]m= \frac{0-3}{-3-0} [/tex]

[tex]m= \frac{-3}{-3} [/tex]

[tex]m=1[/tex]

Point Slope Form:  [tex](y-y1)=m(x-x1)[/tex]

[tex](y-3)=1(x-0)[/tex]

[tex](y-3)=(x-0)[/tex]

[tex](y-3)=(x)[/tex]
Lilithidn
[tex] A (0,3), \ \ B (-3,0) \\\\\\ First \ find \ the \ slope \ of \ the \ line \ thru \ the \ points \: \\ \\ m= \frac{y_{2}-y_{1}}{x_{2}-x_{1} } \\ \\m=\frac{ 0-3}{-3-0} = \frac{-3}{-3}=1 \\ \\ Use \ point \ form \ of \ a \ line\ with \ one \ point: \\ \\ y-y_{1} =m(x-x _{1}) \\ \\m=1,\ \ x_{1}=0, \ \ y_{1}=3 \\ \\ y-3= (x-0}\\\\y= x +3 [/tex]
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