Answered

Discover new knowledge and insights with IDNLearn.com's extensive Q&A database. Ask your questions and receive reliable and comprehensive answers from our dedicated community of professionals.

 what is the equation of a parabola whose vertex is (-6,0) and whose graph is half as tall as y=x^2 and opens upside down?

Sagot :

[tex]The\ vertex\ form:y=a(x-h)^2+k\\\\vertex\ (h;\ k)\to(-6;\ 0)\\\\then:y=a[x-(-6)]^2+0=a(x+6)^2\\\\graph\ is\ half\ as\ tall\ as\ y=x^2\ and\ o\ pens\ upside\ down\ then\ a=-2\\\\Answer:y=-2(x+6)^2[/tex]


If I understood correctly "graph is half as tall as y=x^2".

Thank you for joining our conversation. Don't hesitate to return anytime to find answers to your questions. Let's continue sharing knowledge and experiences! IDNLearn.com is dedicated to providing accurate answers. Thank you for visiting, and see you next time for more solutions.