Answered

Get the information you need with the help of IDNLearn.com's extensive Q&A platform. Get the information you need from our community of experts who provide accurate and comprehensive answers to all your questions.

Find the equation of the circle passing through the origin and with the center (3,5)
The answer should be written in the form (x-h) squared + (y-h)squared = radius squared
Thanks!!

Sagot :

Luanaidn
[tex]Equation\ of\ circle\\\\\ r^2=(x-a)^2+(y-b)^2\\\\ a,b- \ coordinates\ of\ center\ of\ circle\\\\\ (a,b)=(3,5)\\\\ r^2=(x-3)^2+(y-5)^2\\\\\ Substituting\ point\ (0,0)-origin\\\\ r^2=(0-3)^2+(0-5)^2\\\\ r^2=(-3)^2+(-5)^2\\\\ r^2=9+25=36\\ r=6\\\\ Answer:\ \ 36=(x-3)^2+(y-5)^2[/tex]