IDNLearn.com is the place where your questions are met with thoughtful and precise answers. Discover comprehensive answers to your questions from our community of knowledgeable experts.

Find the equation of the circle passing through the origin and with the center (3,5)
The answer should be written in the form (x-h) squared + (y-h)squared = radius squared
Thanks!!


Sagot :

[tex]Equation\ of\ circle\\\\\ r^2=(x-a)^2+(y-b)^2\\\\ a,b- \ coordinates\ of\ center\ of\ circle\\\\\ (a,b)=(3,5)\\\\ r^2=(x-3)^2+(y-5)^2\\\\\ Substituting\ point\ (0,0)-origin\\\\ r^2=(0-3)^2+(0-5)^2\\\\ r^2=(-3)^2+(-5)^2\\\\ r^2=9+25=36\\ r=6\\\\ Answer:\ \ 36=(x-3)^2+(y-5)^2[/tex]
We appreciate your participation in this forum. Keep exploring, asking questions, and sharing your insights with the community. Together, we can find the best solutions. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and come back for more insightful information.